Applications of integration
Mass, centroids, and moments
Moments weight mass by distance from an axis. First moments locate a balance point; second moments measure squared-distance distribution.
1. A uniform rod
1 / 4m=L,\quad M=\frac{L^2}{2},\quad\bar x=\frac L2 A rod on [0,L] with density 1 has mass L. Its first moment about zero is ∫₀ᴸx dx=L²/2, so its center of mass is L/2.
- m
- 2
- M
- 2
- x̄
- 1
The shading represents the stated rod density or lamina. Moment formulas specify the axis; mass, centroid and second moments are different quantities.
2. A triangular lamina
2 / 4m=\frac{b^2}{2},\quad(\bar x,\bar y)=\left(\frac{2b}{3},\frac b3\right) For uniform density 1 under y=x on [0,b], mass is b²/2. My=∫x·x dx=b³/3 and Mx=∫x²/2 dx=b³/6. Hence the centroid is (2b/3,b/3).
- m
- 0.5
- x̄
- 0.666667
- ȳ
- 0.333333
The shading represents the stated rod density or lamina. Moment formulas specify the axis; mass, centroid and second moments are different quantities.
3. Second moments about axes
3 / 4I_x=\frac{b^4}{12},\quad I_y=\frac{b^4}{4} For the same triangular lamina, Ix=∫₀ᵇx³/3 dx=b⁴/12 and Iy=∫₀ᵇx²·x dx=b⁴/4. These are about the coordinate axes, not axes through the centroid.
- Iₓ
- 0.083333
- Iᵧ
- 0.25
- Iᵧ/Iₓ
- 3
The shading represents the stated rod density or lamina. Moment formulas specify the axis; mass, centroid and second moments are different quantities.
4. Nonuniform density
4 / 4\rho(x)=x,\quad m=\frac{b^2}{2},\quad\bar x=\frac{2b}{3} For a rod with density ρ(x)=x on [0,b], mass is b²/2 and first moment is b³/3. The center of mass 2b/3 lies toward the denser right end, beyond the midpoint.
- m
- 0.5
- M
- 0.333333
- x̄
- 0.666667
The shading represents the stated rod density or lamina. Moment formulas specify the axis; mass, centroid and second moments are different quantities.